Umstellen < Klassen 8-10 < Schule < Mathe < Vorhilfe
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(Frage) beantwortet  | | Datum: | 09:49 Di 17.08.2010 | | Autor: | Kuriger |
Hallo, ich versuche mich gerade bei der Formelumstellung nach [mm] \phi
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[mm] p_s [/mm] = 6.107 * [mm] 10^{\bruch{7.5 \phi}{\phi + 237}}
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log [mm] (\bruch{p_s}{6.107}) [/mm] = [mm] \bruch{7.5 * \phi}{\phi + 237}
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(log [mm] (\bruch{p_s}{6.107})) [/mm] * [mm] (\phi [/mm] + 237) = 7.5 * [mm] \phi
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((log [mm] (\bruch{p_s}{6.107})) [/mm] * [mm] (\phi [/mm] + 237)) - 7.5 * [mm] \phi [/mm] = 0
(log [mm] (\bruch{p_s}{6.107}* \phi) [/mm] + 237* log [mm] (\bruch{p_s}{6.107}) [/mm] - 7.5 * [mm] \phi [/mm] = 0
[mm] \phi [/mm] * (log [mm] (\bruch{p_s}{6.107}) [/mm] - 7.5) = - 237* log [mm] (\bruch{p_s}{6.107})
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[mm] \phi [/mm] = [mm] \bruch{- 237* log (\bruch{p_s}{6.107})}{log (\bruch{p_s}{6.107}) - 7.5}
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oder wie würde die Umstellung aussehen?
Danke, Gruss Kuriger
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(Antwort) fertig  | | Datum: | 09:55 Di 17.08.2010 | | Autor: | fred97 |
Du hast alles richtig gemacht
FRED
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